A25.0 ml solution of .0600 m edta was added to a 57.0 ml sample containing an unknown concentration of v3+. all v3+ present formed a complex, leaving excess edta in solution.

this solution was back-titrated with a 0440 m ga3+ solution until all the edta reacted requiring 14.0 ml of the ga3+ solution.

what was the original concentration of the v3+ solution?

Explanation:

Let us assume that the ratio for the given reaction is 1:1.

Therefore, we will calculate the moles of as follows.

   Moles of solution = molarity × volume (L)

                              = 0.0440 M × 0.014 L

                              = 0.000616 moles

Moles of excess EDTA = 0.000616 moles

Also, the initial moles of EDTA will be calculated as follows.

     Total initial moles of EDTA = 0.0600 M × 0.025 L

                                                 = 0.0015

Therefore, moles of EDTA reacted with will be as follows.

                = 0.0015 - 0.000616

                = 0.00088 moles

Since, we have supposed a 1 : 1 ratio between and EDTA .

So, moles of = 0.00088 moles

Now, we will calculate the molarity of as follows.

       Molarity of solution =

                             =

                             = 0.015 M

Thus, we can conclude that the original concentration of the solution is 0.015 M.

no

explanation:

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both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .