Atrial of this decomposition experiment, using different quantities of reactants than those listed in the question above produced the following data: volume of o2 produced at room conditions 280 ml barometric pressure 740 torr temperature of water 24°c termperature of o2 25°c vapor pressure due to water at 25°c 22.4 torr for the conditions listed above, calculate the volume of o2(g) produced at standard conditions of temperature and pressure. (enter your answer in liters)

Answer : The volume of produced at standard conditions of temperature and pressure is 0.2422 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = (740-22.4) torr = 717.6 torr

= final pressure of gas at STP= 760 torr

= initial volume of gas = 280 mL

= final volume of gas at STP = ?

= initial temperature of gas =

= final temperature of gas =

Now put all the given values in the above equation, we get:

Therefore, the volume of produced at standard conditions of temperature and pressure is 0.2422 L

i believe it is a.) released into

explanation: