Find the original concentration of a solution diluted from 15.00 ml to 125.0 ml with a final concentration of 0.00383 m

0.03192 M

We are given;

We are required to calculate the initial concentration, M1 before dilution.

Rearranging the formula;

M1 = M2V2 ÷ V1

    = ( 0.00383 M × 0.125 L) ÷ 0.015 L

   = 0.03192 M

Therefore, the original concentration of the solution before dilution is 0.03192 M

output?

explanation: