40.0 g neon and 40.0 g helium has a total pressure of 0.900 atm, what is the the partial pressure of the neon?

P₁ = 0.18 atm

Explanation:

Given data:

Mass of neon = 40 g

Mass of helium = 40 g

Total pressure = 0.90 atm

Partial pressure of neon = ?

Solution:

Number of moles of helium

Number of moles of helium = mass/ molar mass

Number of moles of helium = 40 g/ 4 g/mol

Number of moles of helium = 10 mol

Number of moles of neon:

Number of moles of neon = mass/ molar mass

Number of moles of neon = 40 g/ 20g/mol

Number of moles of neon = 2 mol

Partial Pressure of neon:

P₁ = [ n₁ / nt ] × Pt

P₁ = partial pressure of neon

n₁ = 2 mol

nt = 10 mol + 2 mol = 12 mol

P₁ =  [ 2 mol /  12 mol ]× 0.900 atm

P₁ = 0.2× 0.900 atm

P₁ = 0.18 atm