Consider the reactionn2o4(g)→2no2(g) where n2o4 is colorless and no2 is brown. at a temperature of 5∘c, the reaction is colorless at equilibrium. this indicates that the equilibrium constant for this reaction at this temperature is consider the reactionwhere is colorless and is brown. at a temperature of 5, the reaction is colorless at equilibrium. this indicates that the equilibrium constant for this reaction at this temperature . negative. b. large. c. small (less than 1).d. zero, because equilibrium can only be obtained at room temperature.

Small (less than 1)

Explanation:

When a reversible reaction is at equilibrium, the reactants are forming the products at the same speed that the products are forming the reactants, so there is no visual difference. The equilibrium can be characterized by a constant (Kc). For a generic reaction:

aA + bB ⇄ cC + dD

Kc =

For the given reaction: N₂O₄(g) ⇄ 2NO₂(g)

Kc = [NO₂]²/[N₂O₄]

If only NO₂ has color, and the solution is colorless, there are a few NO₂ in it, and [N₂O₄]>[NO₂], so Kc will be small, and less the 1, because for Kc = 1, [N₂O₄] = [NO₂]².

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year