12) what is the mass percent of phosphorus in mgkpo4 6h2o? (15 pts)

11.62%

Explanation:

We are given;

We are required to calculate the mass percent of phosphorus in the above compound.

In this case;

Atomic mass of Mg = 24.305 g

Atomic mass of K = 39.098 g

Atomic mass of P = 30.974 g

Atomic mass of O = 16.0 g

Molar mass of water is 18.02 g/mol

= (1 × 24.305 g) + (1 × 39.098 g) + (1 × 30.974 g) + (4 × 16.0 g) + (6 ×18.02 g)

= 266.497 g

But, mass of P in the compound is 30.974 g

Therefore;

Mass % of P = (30.974 g ÷ 266.497 g) × 100

                    = 11.62%

Thus, the mass percent of phosphorus in the compound is 11.62%

metric time was an attempt to create a standard unit of time based off of 10, but it never took off an is not included in the metric system (si)