the volume of a gas at stp is 7.30 l. what is the quantity of gas in this sample?

The quantity of gas is  0.33 mol.

Explanation:

Given data:

Volume of gas = 7.30 L

Pressure of gas = 1 atm

Temperature of gas = 273 K

Amount of gas = ?

Solution:

PV = nRT

n = PV/ RT

n = 1 atm. 7.30 L / 0.0821 atm. L. mol⁻¹. K⁻¹ × 273 K

n  = 7.30 atm. L / 22.4 atm. L. mol⁻¹

n = 0.33 mol

0.326 moles

We are given;

We are supposed to determine the quantity of the gas sample;

In this case;

1 mole = 22.4 L

Therefore;

Therefore,

Moles of the gas sample = 7.30 L ÷ 22.4 L

                                        = 0.326 moles

Therefore, the quantity of the gas sample is 0.326 moles

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