Chemistry, 20.11.2019 09:31 Tok

What is the molarity of a solution prepared by dissolving 10.7 g nai in 0.250 l? 0.0714
0.286
42.8
2.86×10−4
none of the above

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Answer from: LtotheJ0225

The molarity of a solution prepared by dissolving 10.7 g NaI in 0.250 L is 0.286 mol/L

Explanation:

Molarity M is defined as the number of moles of solute that are dissolved in a certain volume, generally expressed in liters:

$Molarity=\frac{number of moles of solute}{solution volume}$

Then you must first know how many moles represent 10.7 g of NaI. For that you must know the mass of the compound, that is, the mass that contains 1 mol of NaI. For that you know that:

Na: 23 g/molI: 126.9 g/mol

Then:

NaI: 23 g/mol + 126.9 g/mol = 149.9 g/mol

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three. Remember that proportionality is a constant relationship or ratio between different magnitudes.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:

a ⇒ b

c ⇒ x

$x=\frac{c*b}{a}$

Then you can apply a rule of three to know how many moles represent 10.7 g of NaI as follows: if 149.9 g are contained in one mole of NaI, 10.7 g are contained in how many moles of the compound?

$molesofNaI=\frac{10.7grams*1mole}{149.9 grams}$

moles of NaI= 0.0714

Then the molarity is

$Molarity=\frac{0.0714 moles}{0.250 L}$

Molarity=0.286

Finally, the molarity of a solution prepared by dissolving 10.7 g NaI in 0.250 L is 0.286 mol/L

Answer from: Quest

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Answer from: Quest

The answer to your question really depends on three things: how much water you have, how cold it is to start out, and how cold the things around it are. water actually freezes when it gets to 32 degrees fahrenheit (0 degrees celsius), but the time it takes to get there may be different. let's start with the first. if you take two glasses, and fill one with a tiny bit of water, and the other about halfway, then put them both in the freezer, the one with less water will freeze first (you can try this at home, but i recommend using plastic cups and not glass ones). now let's move on to the second part. let's say you have two glasses, and you fill one with really cold water that has been in the refrigerator, and the other with really hot water from the sink. if you put both of them in the freezer, the one that started out colder will freeze first. for the third part, let's imagine that you have two glasses with the same amount of water in them, and the water is at the same temperature. imagine putting one outside on a really really cold day in georgia, and having a friend in alaska put one outside on the same day. since it would be so much colder in alaska, the glass of water there would freeze before yours. so, if you took a tiny bit of really cold water in a glass, and put it outside on a cold day in alaska, it would freeze a lot faster than a big glass of hot water outside on a cold day in georgia.

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What is the molarity of a solution prepared by dissolving 10.7 g nai in 0.250 l? 0.0714
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