Insert the values from the question above for x, y, z, & n into kxfey(c204)z nh20 anod provide the correct coefficients to balance the following equation fe(nh4 )2(so4 )2.6h20+_h2c204+_k2c204+-h202 → k, fey c204)z nh20+(nh4)2so4+ h2s04+h20 (hint: remember h202, an oxidizing agent, was used in the synthesis, so you'll need to do a redox balance. start with just the iron ions, balance the reaction, and then add the full formulas.)