Heat is transferred at a rate of 2 kw from a hot reservoir at 775 k to a cold reservoir at 300 k. calculate the rate at which the entropy of the two reservoirs changes. (round the final answer to six decimal places.)

Explanation:

The given data is as follows.

           Q = 2 kW,         = 775 K

        = 300 K

The relation between entropy and heat energy is as follows.

Therefore, calculate the entropy at each temperature as follows.

                            =

                            = kW/K

Also,        

                            =

                            = kW/K

Hence, the change in entropy will be calculated as follows.

                     = kW/K

                     = kW/K

or,                 = 0.0041 kW/K

Thus, we can conclude that the rate at which the entropy of the two reservoirs changes is 0.0041 kW/K.

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

subscribe to my yt channel yoongi jmz

follow my insta yoongi_jams

stan bts