500. ml of gas is contained at stp. the volume changes to 560 ml at 20.°c
what is the pressure (in atm)?

P₂ = 0.96 atm

Explanation:

Given data:

Initial volume = 500 mL

Initial pressure = 1 atm

Initial temperature = 273 K

Final volume = 560 mL

Final temperature = 20°C (20+ 273 = 293K)

Final pressure = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

P₂ = P₁V₁ T₂/ T₁ V₂  

P₂ = 1 atm × 500 mL × 293 K / 273 K × 560 mL  

P₂ = 146500 atm .mL. K /  152880 k.mL

P₂ = 0.96 atm

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current