Draw the organic product formed when the structure shown below undergoes a reaction with nanh2. there is no aqueous workup in this reaction.

Prop-1-yn-1-ide

Explanation:

In this case, we will have an acidic hydrogen upon the left carbon in the alkyne. In the presence of a base, we can remove this hydrogen. In this reaction the base will be . The amidure ion will remove the hydrogen of the alkyne to produce a carboanion. (See figure)

Ifound this on google “these two compounds have a different ionic structure. caesium ion is larger in size when compared to the sodium ion. the charge gets more area to spread out evenly. so caesium chloride has a lower melting point than sodium chloride.” i hope this you for what your looking for

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