Photosynthesis allows plants to turn light energy into chemical energy by forming glucose from carbon dioxide and water: 6co2(g) + 6h2o(l) → c6h12o6(g) + o2(g) δhrxn = 2802.8 kj the glucose is then used to form complex carbohydrates that the plant needs to survive. a 1.70 lb sweet potato is approximately 73% water by mass. if the remaining mass is made up of carbohydrates derived from glucose (mw = 180.156 g/mol), how much carbon dioxide (mw = 44.01 g/mol) was needed to grow this sweet potato? g how much light energy does it take to grow the 1.70 lb. sweet potato if the efficiency of photosynthesis is 0.86%? kj

305 g of CO₂

3.77 × 10⁵ kJ

Explanation:

Let's consider the global reaction for photosynthesis.

6 CO₂(g) + 6 H₂O(l) → C₆H₁₂O₆(g) + 6 O₂(g)  ΔHrxn = 2802.8 kJ

A 1.70 lb sweet potato is approximately 73% water by mass. If the remaining mass is made up of carbohydrates derived from glucose (MW = 180.156 g/mol), how much carbon dioxide (MW = 44.01 g/mol) was needed to grow this sweet potato?

Let's consider the following relations:

Then, for a 1.70 lb potato:

How much light energy does it take to grow the 1.70 lb. sweet potato if the efficiency of photosynthesis is 0.86%?

According to the enthalpy of the reaction, 2802.8 kJ are required to produce 1 mole of glucose. Then, for a 1.70 lb potato:

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.

answer; 4 electrons;