What temperature change in celsius degrees is produced when 800. j is absorbed by 100. g of water?

ΔT  = 1.914 °C

Explanation:

Given data:

Temperature change = ?

Heat absorbed = 800 j

Mass of water = 100 g

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m.c. ΔT

ΔT  = Q / m.c

ΔT  = 800 j/ 100 g. 4.18 j/g.°C

ΔT  = 800 j/ 418 j /.°C

ΔT  = 1.914 °C

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