How many molecules are 9.11×10²³ atoms of ca(ch3coo)2 step by step

5.48422× molecules

Explanation:

1 atom has 6.02×10²³ molecules (Avagadro's number)

So, set it up like this:

9.11×10²³atoms ×

Hence, multiply to get your

5.48422× molecules

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answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.