Chemistry brainiest 15 points
magnesium has two valence electrons and oxygen has six valence electrons. the electronegativity difference between the two elements is 2.13.

how can the octet rule be used to explain the bonding between magnesium and oxygen?

oxygen needs access to two electrons to satisfy the octet rule. magnesium prefers to lose two valence electrons to satisfy the octet rule. oxygen can remove two electrons from magnesium, forming ions; leading to an ionic bond.

oxygen needs to lose six electrons to satisfy the octet rule. magnesium needs access to six valence electrons to satisfy the octet rule. magnesium can remove six electrons from oxygen, forming ions and leading to an ionic bond.

oxygen needs access to two electrons to satisfy the octet rule. magnesium prefers to lose two valence electrons to satisfy the octet rule. magnesium and oxygen can share two electrons, leading to a covalent bond.

oxygen needs to lose six electrons to satisfy the octet rule. magnesium needs access to six valence electrons to satisfy the octet rule. magnesium and oxygen can share six electrons, leading to a covalent bond.

A) Oxygen needs access to two electrons to satisfy the octet rule. magnesium prefers to lose two valance electrons to satisfy the octet rule.Oxygen can remove the two electrons from magnesium, forming ions leading to an ionic bond.

Explanation:

Oxygen is present in group sixteen and have six valance electrons. while magnesium is alkaline earth metal and present in group two and have two valance electrons.

Oxygen needs two electron to complete the octet while magnesium need to lose the two electrons to get the complete octet.

When oxygen is combine with magnesium it gain its two valance electrons and form anion while magnesium loses its two electron to wards oxygen and form cation. The bond form between them is ionic because one is metal and other is non metal and electrons are completely transfer from magnesium to oxygen.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml