How much heat will be absorbed by 25g of chloroform when its temperature started at 67.0c and after it was 112.0c

Q = 1102.5 j

Explanation:

Given data:

Mass of chloroform = 25 g

Initial temperature = 67.0°C

Final temperature = 112.0°C

Heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Specific heat capacity of chloroform = 0.98 j/g.°C

ΔT  = T2-T1

ΔT = 112.0°C - 67.0°C

ΔT = 45°C

Q = m.c. ΔT

Q = 25 g × 0.98 j/g.°C × 45°C

Q = 1102.5 j

it would be d. henry moseley

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