Determine the mole fractions of each component in the vapor phase of the vapor in equilibrium with a 1: 1 molar ratio of hexane (c6h14) and cyclohexane (c6h12). the equilibrium vapor pressures of hexane and cyclohexane are equal to 151.4 torr and 97.6 torr respectively

mole fraction of hexane = 0.61 and mole fraction of cyclohexane = 0.39

Explanation:

According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.

and

where, x = mole fraction

= pressure in the pure state

According to Dalton's law, the total pressure is the sum of individual pressures.

,  

,  

= mole fraction of hexane in vapor phase

Thus the mole fraction of hexane in the vapor above the solution is 0.61 and mole fraction of cyclohexane in the vapor above the solution is 0.39

h let me think

58750.08068 is the answer i think