Arigid cylinder with a movable piston contains a sample of hydrogen gas at 330k the sample has a pressure of 150 kpa and a volume of 3.50l what is the volume of this sample at stp

V₂ = 4.343 L

Explanation:

Given data:

Initial pressure = 150 KPa ( 150/101.325 = 1.5 atm)

Initial volume = 3.50 L

Initial temperature = 330 K

Final pressure = 1 atm

Final temperature = 273 K

Final volume = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1.5 atm × 3.50 L × 273 K / 330 K × 1 atm

V₂ = 1433.25 atm .L. K / 330 K. atm

V₂ = 4.343 L

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.