Using your knowledge of reactions and mechanisms, draw the mechanism for the formation of 2-methylpropene from 2-methyl-2-propanol

Here's what I get  

Explanation:

The reaction is an E1 elimination of an alcohol to form an alkene. It has three steps:

1. Protonation

The alcohol is protonated with aqueous sulfuric acid to convert it into a better leaving group.

2. Loss of the leaving group

A water molecule leaves in a unimolecular process to form a stable 3° carbocation.

3. Loss of an α-hydrogen

A water molecule removes an α-hydrogen, forming 2-methylpropene and regenerating the original hydronium ion.

i believe the answer is true.