Calculate the number of carbon atoms in 1.50g of c6h12o6

Number of C-atoms =  3.01 *10^22

Explanation:

Step 1: Data given

Mass of glucose = 1.50 grams

Molar mass of Glucose = 180.156 g/mol

Molar mass of carbon = 12.01 g/mol

Step 2: Calculate number of moles glucose

Number of moles glucose = mass glucose / molar mass glucose

Moles glucose = 1.50 grams / 180.156 g/mol

Moles glucose = 0.00833 moles

Step 3: Calculate formula units of glucose

0.00833 moles glucose * 6.02 *10^23 = 5.01 *10^21

Step 4: Calculate number of carbon atoms

Glucose has 6 C'atoms in it's molecular formule

Number of C-atoms = 5.01 *10^21 * 6 = 3.01 *10^22

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

the answer would be b i believe