What volume of 0.20mnacl(aq) contains 10.0g of nacl (molar mass 58g/mol)?

We have that for the Question "What volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol)?" it can be said that The volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol) is

V=0.862L

From the question we are told

What volume of 0.20MNaCl (aq) contains 10.0g of NaCl (molar mass 58g/mol)?

Generally the equation for the  morality  is mathematically given as

V=0.862L

Therefore

The volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol) is

V=0.862L

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The volume of 0.20M NaCl solution containing 10g of NaCl will be 34.48 ml.

Molarity can be defined as the moles of solute in a liter of solution.

The 10 g of NaCl will be:

moles of NaCl =

Moles of NaCl = 0.172 moles

Volume of NaCl solution = 0.172 0.20

Volume of NaCl solution = 0.0344 liters

1 liter = 1000 ml

0.0344 liters = 0.0344 1000 ml

Volume of 0.20M NaCl solution containing 10g of NaCl will be 34.48 ml.

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"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"