If 10.62 ml of a standard 0.3330 m koh solution reacts with 98.20 ml of ch3cooh solution, what is the molarity of the acid solution?

0.036 M of

Explanation:

It is an example of acid-base neutralization reaction.

KOH  +  ---->   +  

Base           Acid                           Salt                                    

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity=

No.of moles= Molarity × Volume of the Particular Solution

Therefore,

------------------------------(1)

where

= Molarity of Acid

= Volume of Acid

= Molarity of Base

= Volume of Base

=0.3330 M

=10.62 mL

=98.2 mL

=??(in M)

Plugging in Equation 1,

0.3330 × 10.62 =  × 98.2  

=

=0.036 M

here's the link to your question!

explanation:

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: