A2.00-l sample of was collected over water at a total pressure of 750. torr and 26 °c. when the was dried (water vapor removed), the gas had a volume of 1.93 l at 26 °c and 750. torr. calculate the vapor pressure of water at 26 °c.

The vapor pressure of water at 26 °C = 26.25 atm

Explanation:

Using Boyle's law  

Given ,  

V₁ = 2.00 L

V₂ = 1.93 L

P₁ = ?

P₂ = 750 torr

Using above equation as:

Vapor pressure = Total pressure - Partial pressure of oxygen gas = 750 - 723.75 atm = 26.25 atm

The vapor pressure of water at 26 °C = 26.25 atm

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

answersilicon (si); oxygen (o);