Calculate δh∘f (in kilojoules per mole) for benzene, c6h6, from the following data: 2c6h6(l) + 15o2(g)→12co2(g)+6h2o(l) δh∘=−6534.0 kjδh∘f co2=−393.5 kj/molδh∘f h2o=−285.8 kj/mol express the enthalpy change in kilojoules per mole to three significant digits.

48.6 kJ/mol

Explanation:

The balanced chemical reaction is,

The expression for enthalpy change is,

where,

n = number of moles

(as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

Therefore, the enthalpy change for benzene is 48.6 kJ/mol

answer: lol

explanation:

lol

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.