If a buoyant force of 6 n acts on a block placed in water what is the weight of the water that the block displaces?

6 N  

Explanation:

Per Archimedes' Principle,  the buoyant force on an object is equal to the weight of the fluid displaced.

If the buoyant force is 6 N, the weight of the water displaced is 6 N.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

i think slash and