You determine the volume of your plastic bag (simulated human stomach) is 1.05 l.

how many grams of nahco3 (s) are required to fill this container given a 70.2% co2 recovery, assuming the other contents in the bag take up a negligible volume compared to the gas.

the temperature of the room is 21.5 â°c and the atmospheric pressure is 753.5 mmhg.

We need 5.1 grams of NaHCO3

Explanation:

Step 1: Data given

volume of the plactic bag = 1.05 L

Recovery = 70.2 %

Temperature = 21.5°C

Pressure = 753.5 mmHg

Step 2: ideal gas law

p*V = n*R*T

with p = the pressure = 735.5 mmHg = 0.9914 atm

with V= the volume = 1.05 L

with n = the number of moles =  unknown

with R =  Gas constant = 0.0821 L*atm/mol*K

with T =the temperature = 21.5 °C = 296.65 Kelvin

Calculate the number of moles:

n = p*V / RT

n = (0.9914 * 1.05)/(0.0821 * 296.65)

n =0.0427 mol

Percentage recovery of carbon dioxide gas =  70.2%

Step 3: Calculate actual moles of CO2 formed

Actual moles of carbon dioxide formed: 70.2 % of 0.0427 mol

0.702 * 0.0427 = 0.0300 mol

Step 4: Calculate moles NaHCO3

2NaHCO3 → Na2CO3 + H2O + CO2

For 2 mole NaHCO3 consumed, we get 1 mole Na2CO3, 1 mole H2O and 1 mole CO2

2*0.0300 = 0.06 mol

Step 5: Calculate mass of NaHCO3

Calculate mass of NaHCO3

Mass NaHCO3 = moles NaHCO3 * Molar mass NaHCO3

Mass NaHCO3 = 0.06 mol * 84 g/mol

Mass NaHCO3 = 5.1 grams

We need 5.1 grams of NaHCO3

h let me think

definition

                    entropy is a measure of the randomness or the extent of disorder of a chemical process.

                      enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

                        entropy is measured in joule per kelvin (jk⁻¹)   whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

                            entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

                              in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.