A32.4 g iron rod, initially at 21.6 ∘c, is submerged into an unknown mass of water at 63.1 ∘c, in an insulated container. the final temperature of the mixture upon reaching thermal equilibrium is 59.6 ∘c. you may want twhat is the mass of the water?

 37.8 grams

Explanation:-

As we know that

        .................(1)

where,

q = heat absorbed or released

= mass of iron rod = 32.4 g

= mass of water = ?

= final temperature =  

= temperature of iron rod =

= temperature of water =

= specific heat of iron rod =

= specific heat of water=

Now put all the given values in equation (1), we get

Therefore, the mass of the water is 37.8 grams

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explanation:

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