Asample of an unknown metal has a mass of 58.932g. it has been heated to 101.00 degrees c, then dropped quickly into 45.20 ml of pure water. the temperature of the water changed from 21 degrees c to 23.68 degrees c. what is the specific heat of the metal? specific heat of water is 4.184 j/g c.

0.111 J/g°C

Explanation:

We are given;

Mass of the unknown metal sample as 58.932 g Initial temperature of the metal sample as 101°CFinal temperature of metal is 23.68 °CVolume of pure water = 45.2 mL

But, density of pure water = 1 g/mL

Therefore; mass of pure water is 45.2 g Initial temperature of water = 21°CFinal temperature of water is 23.68 °CSpecific heat capacity of water = 4.184 J/g°C

We are required to determine the specific heat of the metal;

Step 1: Calculate the amount of heat gained by pure water

Q = m × c × ΔT

For water, ΔT = 23.68 °C - 21° C

                       = 2.68 °C

Thus;

Q = 45.2 g × 4.184 J/g°C × 2.68°C

    = 506.833 Joules

Step 2: Heat released by the unknown metal sample

We know that, Q =  m × c × ΔT

For the unknown metal, ΔT = 101° C - 23.68 °C

                                              = 77.32°C

Assuming the specific heat capacity of the unknown metal is c

Then;

Q = 58.932 g × c × 77.32°C

   = 4556.62c Joules

Step 3: Calculate the specific heat capacity of the unknown metal sampleWe know that, the heat released by the unknown metal sample is equal to the heat gained by the water.Therefore;

4556.62c Joules = 506.833 Joules

c = 506.833 ÷4556.62

  = 0.111 J/g°C

Thus, the specific heat capacity of the unknown metal is 0.111 J/g°C

The answer to your question really depends on three things: how much water you have, how cold it is to start out, and how cold the things around it are. water actually freezes when it gets to 32 degrees fahrenheit (0 degrees celsius), but the time it takes to get there may be different.  let's start with the first. if you take two glasses, and fill one with a tiny bit of water, and the other about halfway, then put them both in the freezer, the one with less water will freeze first (you can try this at home, but i recommend using plastic cups and not glass ones).  now let's move on to the second part. let's say you have two glasses, and you fill one with really cold water that has been in the refrigerator, and the other with really hot water from the sink. if you put both of them in the freezer, the one that started out colder will freeze first.  for the third part, let's imagine that you have two glasses with the same amount of water in them, and the water is at the same temperature. imagine putting one outside on a really really cold day in georgia, and having a friend in alaska put one outside on the same day. since it would be so much colder in alaska, the glass of water there would freeze before yours.  so, if you took a tiny bit of really cold water in a glass, and put it outside on a cold day in alaska, it would freeze a lot faster than a big glass of hot water outside on a cold day in georgia.