Question is above pls
a)2
b)3
c)4
d)5

5 will come in blank

4KMnO₄ > 2K₂O + 4MnO + 5O₂

Explanation:

Reaction:

4KMnO₄ > 2K₂O + 4MnO + O₂

this reaction is the dissociation reaction in which KMnO₄ is break down into its component.

KMnO₄ upon dissociation gives Potassium oxide, manganese oxide and liberate oxygen

Balance Chemical Equation:

A balanced chemical equation is that in which the the number of the reactant atoms equal to the number of the product atom.

For example if the oxygen at the reactant side is 4, the number of oxygen should be 4 on the product side.

So for this purpose  we have to balnce the reaction and number of atoms on each side of the arrow

if we see the given Equation

Numbers of atom on reactant Side:

K = 4

Mn = 4

O = 16

Numbers of atom on reactant Side:

K = 4

Mn = 4

O = 6 instead of blank oxygen molecule

so from the above data we have 10 oxygen less.

If we put the 5 in the blank then we will have 10 oxygen and equation will be balanced

So the balanced Equation will be

4KMnO₄ > 2K₂O + 4MnO + 5O₂

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol