Lithium and fluorine undergo ionic bonding. using the noble gas electron configurations for each (below), explain the process of bonding step by step, using proper grammar and mechanics. noble gas electron configurations: lithium: [he] 2s1 fluorine: [he] 2s22p5

Lithium loses one electron to fluorine and forms ionic bond, having formula .

Explanation:

Lithium is the element of the group 1 and period 2 which means that the valence electronic configuration is .

Fluorine is the element of the group 17 and period 2 which means that the valence electronic configuration is .

Thus, lithium loses 1 electron and become positively charged. Fluorine on the other hand accepts this electron and become negatively charged. This is done in order that the octet of the atoms are complete.  These both ions then form ionic bond as their will be electrostatic interaction between the two oppositely charged ions.

Thus, the formula of calcium chloride is .

sorry idk the answer well to you i have a explaination

explanation: a formula which shows the arrangement of atoms in the molecule of a compound

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.