How many grams of silver chromate will precipitate when 150 ml of 0.500 m silver nitrate are added to 100 ml of 0.400 m potassium chromate

12.44 grams of silver chromate will be formed.

Explanation:

The reaction between silver nitrate ans potassium chromate will be:

Thus two moles of silver ions will react with one mole of chromate ions to give one mole of silver chromate.

Moles of silver ion reacted = moles of silver nitrate taken

moles of potassium chromate taken =

0.075 moles of silver nitrate will react with 0.0375 moles of chromate to give 0.0375 moles of silver chromate.

The molar mass of silver chromate = 331.73g/mol