If 50.00 ml of 1.05 m sodium hydroxide is added to 25.00 ml of 1.88 m hydrochloric acid, with both solutions originally at 24.66°c, what will be the final solution temperature? (assume that no heat is lost to the surrounding air and that the solution produced in the neutralization reaction has a density of 1.02 g/ml and a specific heat of 3.98 jg⁻¹°c⁻¹.)

The final temperature of solution is 24.668883°C

Explanation:

The enthalphy change for the reaction of 1 mol of strong acid and strong base is -57.62 J/mol.

moles of NaOH = 0.0525 mol

moles of HCl = 0.047 mol

Hence ,

          Heat released in this reaction is .047 × 57.62 joules

                                                             = 2.70814 joules

 Final mass of solution is density × final volume.

                                        = 1.02 × 75

                                        =76.5 grams

And ,

       MS = 76.6 × 3.98

              = 304.868

Since,

         Q = M × s × ΔT

Therefore,

                ΔT =

                     =  

                     = 0.00888299198 °C

Hence ,

           Final temperatre = 24.66 + .00888299198

                                        = 24.668883  °C

plants need sunlight, water, and carbon dioxide to make food. plants use the raw materials of water, nutrients they absorb from soil, and carbon dioxide to make sugars the plant can use. energy from the sun and chlorophyll are also needed.