Acetylene gas, c2h2, can be produced by the reaction of calcium carbide and water. cac2(s) + 2h2o(l) --> c2h2(g) + ca(oh)2(aq) how many liters of acetylene at 742 mm hg and 26c can be produced from 2.54 g cac2(s)?

1.0 L

Explanation:

Given that:-

Mass of =

Molar mass of = 64.099 g/mol

The formula for the calculation of moles is shown below:

Thus,

According to the given reaction:-

1 mole of on reaction forms 1 mole of

0.0396 mole of on reaction forms 0.0396 mole of

Moles of = 0.0396 moles

Considering ideal gas equation as:-

where,

P = pressure of the gas = 742 mmHg  

V = Volume of the gas = ?

T = Temperature of the gas =

R = Gas constant =

n = number of moles = 0.0396 moles

Putting values in above equation, we get:

1.0 L of acetylene  can be produced from 2.54 g .

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