Aballoon containing methane gas has a volume of 2.64 l at 31.0 c. what volume will the balloon occupy at 62.0 c?

The balloon will occupy the volume of 2.91 L at 62.0 °C .

Explanation:

Using Charle's law  

Given ,  

V₁ = 2.64 L

V₂ = ?

T₁ = 31.0 °C

T₂ = 62.0 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (31.0 + 273.15) K = 304.15 K  

T₂ = (62 + 273.15) K = 335.15 K  

Using above equation as:

New volume = 2.91 L

The balloon will occupy the volume of 2.91 L at 62.0 °C .

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