Measuring the approximate mass of an ion without using a standard can be accomplished via the following variant of the peak-matching technique describe in the problem 5. the peakmatching technique is used to alternately cause the p+ ion and the (p+1)+ ions to reach the detector. it is assumed that the difference in mass between p+ and (p+1)+ is due to a single 13c replacing a 12c atom. a) if the accelerating voltage for (p+1)+ is labeled v2 and that for p+ is v1, derive a relationship that relates the ratio v2/v1 to the mass of p+ .b) if v2/v1 =0.976542, calculate the mass of the p+ ion.

it's filtration, but this is an assumption so my apologies if i got this

it is the most commonly accepted one

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

4d^55s^1 ( third choice)