Sulfur and fluorine form several different compounds including sulfur hexafluoride and sulfur tetrafluoride. decomposition of a sample of sulfur hexafluoride produces 4.45 g of fluorine and 1.25 g of sulfur, while decomposition of a sample of sulfur tetrafluoride produces 4.43 g of fluorine and 1.87 g of sulfur. calculate the mass of fluorine per gram of sulfur for each sample and show that these results are consistent with the law of multiple proportion.

a)

b)

Explanation:

Sample of sulfur hexafluoride SF₆

4.45 g F / 1.25 g S = 3.56

There is a mass ratio of fluorine to sulfur of 3.51 to 1.

Sample of sulfur tetrafluoride SF₄

4.43 g F / 1.87 g S = 2.37

There is a mass ratio of fluorine to sulfur of 3.51 to 1.

These results are consistent with the law of multiple proportions because the ratio of fluorine in the two compounds is 3:2.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'