gaseous ethane (ch, ch) will react with gaseous oxygen (o2) to produce gaseous carbon dioxide (co2) and gaseous water (h2o). suppose 24 g of
ethane is misced with 16.9 g of oxygen. calculate the maximum mass of water that could be produced by the chemical reaction. round your answer to 2
significant digits.

Mass =  8.1 g

Explanation:

Given data:

Mass of ethane = 24 g

Mass of oxygen = 16.9 g

Mass of water = ?

Solution:

Chemical equation:

2C₂H₆ + 7O₂  → 4CO₂ + 6H₂O

Moles of ethane:

Number of moles = mass/molar mass

Number of moles = 24 g / 30.07 g/mol

Number of moles = 0.8 mol

Moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 16.9 g / 32 g/mol

Number of moles = 0.53 mol

Now we will compare the moles of water with oxygen and ethane.

                         C₂H₆            :             H₂O

                            2               :                6

                         0.8               :           6/2×0.8 = 2.4 mol

                          O₂               :             H₂O

                            7                :              6

                            0.53           :             6/7×0.53= 0.45 mol

It means oxygen is limiting reactant because moles of water produced by given amount of oxygen are less.

Mass of water:

Mass =  number of moles × molar mass

Mass =  0.45 mol ×  18 g/mol

Mass =  8.1 g

the ozone layer acts as a filter for the shorter wavelength and highly hazardous ultraviolet radiation (uvr) from the sun, protecting life on earth from its potentially harmful effects. when the sky is clear, there is an inverse relationship between stratospheric ozone and solar uvr measured at the earth's surface.