Amixture of 50.0 ml of ammonia gas and 60.0 ml of oxygen gas react. if all the gases are at the same temperature and pressure, and the reaction continues till one of the gases is completely consumed, what volume of steam is produced if the other product is nitric oxide gas (no).

The volume of steam produced: 72 ml

Some of the laws regarding gas can apply to ideal gas (volume expansion does not occur when the gas is heated),:

• Boyle's law at constant T,

• Charles's law, at constant P,

• Avogadro's law, at constant P and T,

So that the three laws can be combined into a single gas equation, the ideal gas equation

In general, the gas equation can be written

A mixture of 50.0 mL of ammonia gas and 60.0 mL of oxygen gas reacts at the same temperature and pressure, then we use Avogadro's law:

So the reaction coefficient (showing the mole ratio) that occurs is proportional to the amount of gas volume reacting

Reaction

 4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

This reaction is one of the processes of making nitric acid through the Oswald process

A method that can be used to find limiting reactants is to divide the number of volumes of known reactants by their respective coefficients, and small or exhausted reactants become a limiting reactants

NH₃: volume: reaction coefficient = 50: 4 = 12.5

O₂: volume: reaction coefficient = 60: 5 = 12

So from this comparison, O₂ has the smallest ratio so that it becomes a gas whose volume has completely reacted  (become a limiting reactants )

Then the determination of the volume of steam (H₂O) is based on the volume of O₂

Reaction coefficient H₂O: O₂ = 6: 5

then the volume of steam (H2O):

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oh it is true if thats what you are asking