If you made a voltaic cell out of this reaction, what half-reaction would be occurring at the cathode, and what half-reaction would be occurring at the anode? if you made a voltaic cell out of this reaction, what half-reaction would be occurring at the cathode, and what half-reaction would be occurring at the anode?

a(aq)+1e−→a−(aq) at the cathode and b(aq)→b+(aq)+1e− at the anode.
a(aq)+1e−→a−(aq) at the anode and b(aq)→b+(aq)+1e− at the cathode

A(aq) + 1 e⁻ → A⁻(aq) at the cathode and B(aq) → B⁺(aq) + 1e⁻ at the anode.

Explanation:

In the anode occurs the oxidation, in which the reducing agent loses electrons, and its oxidation number increases.

B(aq) → B⁺(aq) + 1e⁻

In the cathode occurs the reduction, in which the oxidizing agent gains electrons, and its oxidation number decreases.

A(aq) + 1 e⁻ → A⁻(aq)

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

? you expect us to answer this? ? this is your schoolwork, i don't think we can with this, i think it would considering being