Aballoon at 30.0°c has a volume of 222 ml. if the temperature is increased to 56.1°c and the pressure remains constant, what will the new volume be, in ml?

V₂ ≈ 241 mL

Math

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Chemistry

Unit 0

Gas Laws

Charles' Law:

Step 1: Define

V₁ = 222 mL

T₁ = 30.0 °C

T₂ = 56.1 °C

Step 2: Identify Conversions

Temp Conversion

Step 3: Convert

T₁ - 30.0 °C + 273.15 = 303.15 K

T₂ - 56.1 °C + 273.15 = 329.25 K

Step 4: Solve for V₂

Step 5: Check

We are given 3 sig figs. Follow sig fig rules and round.

241.113 mL ≈ 241 mL

metric time was an attempt to create a standard unit of time based off of 10, but it never took off an is not included in the metric system (si)