For the following reaction between mohr's salt (iron as feso_4(nh_4)_2so_4 6h_2o) and potassium dichromate (dichromate as k_2cr_2o_7), determine the volume (in milliliters) of a 0.230 m solution of mohr's salt that is needed to fully react with 0.0500 l of 0.230 m potassium dichromate. (the reaction is shown in its ionic form in the presence of a strong acid.)
cr_2o_7^2- + 6fe^2+ + 14h^+ rightarrow 2cr^3+ + 6fe^3+ + 7h_2o
mohr's salt volume = ml
for the same reaction, what volume (in milliliters) of 0.230 m potassium dichromate is required to fully react with 0.0500 l of a 0.230 m solution of mohr's salt
potassium dichromate volume = ml

Answer :

Part 1 : The volume (in milliliters) of a 0.230 M solution of Mohr's salt is 8.33 mL.

Part 2 : The volume (in milliliters) of a 0.230 M solution of potassium dichromate required is 300 mL.

Explanation :

Part 1 :

Using neutralization reaction:

where,

are the n-factor, molarity and volume of

are the n-factor, molarity and volume of

We are given:

Putting values in above equation, we get:

Conversion used : (1 L = 1000 mL)

Thus, the volume (in milliliters) of a 0.230 M solution of Mohr's salt is 8.33 mL.

Part 2 :

Using neutralization reaction:

where,

are the n-factor, molarity and volume of

are the n-factor, molarity and volume of

We are given:

Putting values in above equation, we get:

Conversion used : (1 L = 1000 mL)

Thus, the volume (in milliliters) of a 0.230 M solution of potassium dichromate required is 300 mL.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

the answer is 1 i believe