Calculate the volume of the gas when the pressure of the gas is 1.60 atm at a temperature of 298 k. there are 160. mol of gas in the cylinder. the value for the universal gas constant r is 0.08206 l⋅atm/(mol⋅k) .
express your answer numerically to four significant figures.

2445 L

Explanation:

Given:  

Pressure = 1.60 atm

Temperature = 298 K

Volume = ?

n =  160 mol

Using ideal gas equation as:

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 08206 L.atm/K.mol

Applying the equation as:

1.60 atm × V = 160 mol × 0.08206 L.atm/K.mol × 298 K  

⇒V = 2445.39 L

Answer to four significant digits, Volume = 2445 L

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the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3