A2.85-g sample of an unknown chlorofluorocarbon is decomposed and produces 564 ml of chlorine gas (cl2) at a pressure of 752 mmhg and a temperature of 298 k. what is the percent chlorine (by mass) in the unknown chlorofluorocarbon

The percentage of chlorine by mass in the unknown chlorofluorocarbon is 56.8%

We'll begin by calculating the number of mole of Cl₂ produced using the ideal gas equation as illustrated below:

PV = nRT

0.989 × 0.564 = n × 0.0821 × 298

0.557796 = n × 24.4658

Divide both side by 24.4658

n = 0.557796 / 24.4658

n = 0.0228 mole

Next, we shall determine the mass of 0.0228 mole of Cl₂

Mass = mole × molar mass

Mass of Cl₂ = 0.0228 × 71

Mass of Cl₂ = 1.62 g

Finally, we shall determine the percentage of chlorine in the unknown chlorofluorocarbon.

Percentage = (mass / total mass) × 100

Percentage of chlorine =(1.62 / 2.85) × 100

Percentage of chlorine = 56.8%

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