Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing copper and silver. cu ( s ) ∣ ∣ cu 2 + ( aq ) ∥ ∥ ag + ( aq ) ∣ ∣ ag ( s ) anode: cathode: net cell reaction:

The half reactions and net cell reaction of the cell is written below.

Explanation:

The given cell is:

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

Half reactions for the given cell follows:

Oxidation half reaction (anode):

Reduction half reaction (cathode):   ( × 2)

Net cell reaction:  

Hence, the half reactions and net cell reaction of the cell is written above.

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when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.