If you mix different amounts of two ideal gases that are originally at different temperatures, what must be true of the final state after the temperature stabilizes? (there may be more than one correct choice.)

a) both gases will reach the same final temperature.

b) the final rms molecular speed will be the same for both gases.

c) the final average kinetic energy of a molecule will be the same for both gases.

a,c are correct

Explanation:

a) On mixing two gases the final temperature of both the gases becomes the same. The heat will flow from high temp. gas to lower temp gas till the temp of both gases become equal (Thermal equilibrium). This is correct.

b) The rms speed of the molecule is inversely proportional to its molar mass so the final rsm will not be the same. This is incorrect.

c) The average kinetic energy of the system will remain the same. Hence this is also correct.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :