Given thath2(g) + f2(g) -> 2hf(g) => ∆h = -546.6 kj . mol-12h2(g) + o2(g) -> 2h20(l) => ∆h = -571.6 kj. mol-1

calculate the value of ∆h for: 2f2(g) + 2h20(l) -> 4hf(g) + o2(g)

The for the reaction is -521.6 kJ.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical equation for the reaction of fluorine and water follows:

The intermediate balanced chemical reaction are:

(1)        ( × 2)

(2)    

The expression for enthalpy of reaction follows:

Putting values in above equation, we get:

Hence, the for the reaction is -521.6 kJ.

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons

1.solid

2.carbon dioxide

3.helium