Chemistry, 03.12.2019 03:31 kedjenpierrelouis

The combustion of 135 mg of a hydrocarbon sample produces 440. mg of co2 and 135 mg h2o. the molar mass of the hydrocarbon sample is 270 g/mol. determine the molecular formula of the hydrocarbon.

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Answer from: rk193140

C10H150

Explanation:

An hydrocarbon is an organic molecule containing only carbon and hydrogen. Hence, for this exercise, we know we are to work with getting the mass of carbon and hydrogen. Kindly note, for convenience sake, we shall be working with unit of mass in grammes. Hence, we must know that 1000mg is present in 1g. To convert the mg unit to g , we simply divide by 1000.

The mass of the hydrocarbon is thus 135/1000 = 0.135g , the mass of carbon iv oxide produced is 440/1000 = 0.44g while the mass of water produced is 135/1000 = 0.135g.

We now proceed to the second part of the question. We can get the mass of hydrogen produced from the mass of water while we can get the mass of carbon produced from the mass of carbon iv oxide.

Since we know the mass of water produced, we now get the number of moles of water produced. To get this, we simply divide the mass of water produced by the molar mass of the water produced. The molar mass of water is 18g/mol. Hence the number of moles is 0.135/18 = 0.0075 moles.

Now, we know that one mole of water contains two moles of hydrogen. Hence, the number of moles of water produced is 2 * 0.0075 = 0.015 mole

To get the number of moles of carbon produced, we simply use the mass of carbon iv oxide produced.

To get the number of moles of carbon iv oxide produced, we simply divide the mass of carbon iv oxide by the molar mass of carbon iv oxide. The molar mass of carbon iv oxide is 44g/mol. The number of moles thus produced is 0.44/44 = 0.01 mole

We now proceed to get the empirical formula of the compound. To do this, we divide each by the smaller number of moles which in this case is that of carbon I.e 0.01 mole

C = 0.01/0.01 = 1

H = 0.015/0.01 = 15

The empirical formula is CH15.

To get the molecular formula, we simply use the empirical formula. The mass of the empirical formula is 27g/mol

Now (CH15)n = 270g/mol

We now get n.

27n = 270

n = 270/27 = 10

The molecular formula is thus C10H150

Answer from: Quest

The answer to your question really depends on three things: how much water you have, how cold it is to start out, and how cold the things around it are. water actually freezes when it gets to 32 degrees fahrenheit (0 degrees celsius), but the time it takes to get there may be different. let's start with the first. if you take two glasses, and fill one with a tiny bit of water, and the other about halfway, then put them both in the freezer, the one with less water will freeze first (you can try this at home, but i recommend using plastic cups and not glass ones). now let's move on to the second part. let's say you have two glasses, and you fill one with really cold water that has been in the refrigerator, and the other with really hot water from the sink. if you put both of them in the freezer, the one that started out colder will freeze first. for the third part, let's imagine that you have two glasses with the same amount of water in them, and the water is at the same temperature. imagine putting one outside on a really really cold day in georgia, and having a friend in alaska put one outside on the same day. since it would be so much colder in alaska, the glass of water there would freeze before yours. so, if you took a tiny bit of really cold water in a glass, and put it outside on a cold day in alaska, it would freeze a lot faster than a big glass of hot water outside on a cold day in georgia.

Answer from: Quest

Hope you find the answer

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The combustion of 135 mg of a hydrocarbon sample produces 440. mg of co2 and 135 mg h2o. the molar m...