What mass of feso4^2- x 6h20 (molar mass=260g/mol) is required to produce 500 ml of a .10m iron (ii) sulfate solution.
a.) 9g
b.) 13g
c.) 36g
d.) 72g

The correct option is: B. 13g

Explanation:

Given: Molar mass of iron (II) sulfate: m = 260g/mol,

Molarity of iron (II) sulfate solution: M =  0.1 M,

Volume of iron (II) sulfate solution: V = 500 mL = 500 × 10⁻³ = 0.5 L           (∵ 1L = 1000mL)

Mass of iron (II) sulfate taken: w = ? g

Molarity:

Here, n- total number of moles of solute, w - given mass of solute, m- molar mass of solute, V- total volume of solution in L

∴ Molarity of iron (II) sulfate solution:  

⇒  

⇒  

⇒  mass of iron (II) sulfate taken:

Therefore, the mass of iron (II) sulfate taken for preparing the given solution is 13 g.

organisms are more likely to be more preserved in mud than sand because mud is moist and wet, while sand is very dry.

3 1/4 %

explanation: