Achemist obtains a 0.300 m solution of hci and adds 10.0 ml of the hci to caco3 how many moles of hci did she add?

Number of moles = 0.003 mol

Explanation:

Given data:

Molarity of HCl = 0.300 M

Volume = 10.0 mL (0.01 L)

Number of moles of HCl added = ?

Solution:

Formula:

Molarity = number of moles / volume in litter

Number of moles = Molarity ×  volume in litter

Number of moles =  0.300 mol/L × 0.01 L

Number of moles = 0.003 mol

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2